(2a+5)(a^2-4x+2)=

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Solution for (2a+5)(a^2-4x+2)= equation: 


Simplifying
(2a + 5)(a2 + -4x + 2) = 0

Reorder the terms:
(5 + 2a)(a2 + -4x + 2) = 0

Reorder the terms:
(5 + 2a)(2 + a2 + -4x) = 0

Multiply (5 + 2a) * (2 + a2 + -4x)
(5(2 + a2 + -4x) + 2a * (2 + a2 + -4x)) = 0
((2 * 5 + a2 * 5 + -4x * 5) + 2a * (2 + a2 + -4x)) = 0
((10 + 5a2 + -20x) + 2a * (2 + a2 + -4x)) = 0
(10 + 5a2 + -20x + (2 * 2a + a2 * 2a + -4x * 2a)) = 0

Reorder the terms:
(10 + 5a2 + -20x + (4a + -8ax + 2a3)) = 0
(10 + 5a2 + -20x + (4a + -8ax + 2a3)) = 0

Reorder the terms:
(10 + 4a + -8ax + 5a2 + 2a3 + -20x) = 0
(10 + 4a + -8ax + 5a2 + 2a3 + -20x) = 0

Solving
10 + 4a + -8ax + 5a2 + 2a3 + -20x = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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